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.5(6x)^2+4=226
We move all terms to the left:
.5(6x)^2+4-(226)=0
We add all the numbers together, and all the variables
.56x^2-222=0
a = .56; b = 0; c = -222;
Δ = b2-4ac
Δ = 02-4·.56·(-222)
Δ = 497.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{497.28}}{2*.56}=\frac{0-\sqrt{497.28}}{1.12} =-\frac{\sqrt{}}{1.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{497.28}}{2*.56}=\frac{0+\sqrt{497.28}}{1.12} =\frac{\sqrt{}}{1.12} $
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